A watertight car is submerged under water. What force is required to open a door of area 1.04 m2 if the average depth of water at the door is 1.56 m?
The force required to open the door would be equal to the pressure of the water at the door multiplied by the area of the door. The pressure of the water at the door can be calculated using the equation P = ρgh, where ρ is the density of water, g is the acceleration due to gravity, and h is the depth of the water. In this case, the pressure would be equal to 1000 kg/m3 * 9.81 m/s2 * 1.56 m = 15,092 N/m2. Multiplying this by the area of the door (1.04 m2) gives a total force of 15,619.68 N.
To determine the force required to open the door of a watertight car submerged underwater, we can use the concept of fluid pressure.
The formula for fluid pressure is given by:
Pressure = Density × Gravitational acceleration × Depth
Here, the density of water is constant and equal to 1000 kg/m3, and the gravitational acceleration is 9.8 m/s2.
Step 1: Calculate the pressure exerted by the water at the door:
Pressure = (Density) × (Gravitational acceleration) × (Depth)
= (1000 kg/m3) × (9.8 m/s2) × (1.56 m)
≈ 15288 Pa
Step 2: Determine the force required to open the door:
Force = Pressure × Area
= (15288 Pa) × (1.04 m2)
≈ 15905.92 N
Therefore, the force required to open the door of area 1.04 m2, when submerged with an average depth of water of 1.56 m, is approximately 15905.92 Newtons.
To calculate the force required to open the door of a watertight car submerged under water, we need to consider the pressure exerted by the water on the door.
The pressure exerted by a fluid is given by the formula:
Pressure = Density x Gravity x Depth
In this case, the fluid is water, so we can use the density of water, which is approximately 1000 kg/m3, and the acceleration due to gravity, which is 9.8 m/s2.
First, we need to calculate the pressure exerted by the water on the door:
Pressure = Density x Gravity x Depth
= 1000 kg/m3 x 9.8 m/s2 x 1.56 m
≈ 15288 Pa
Since pressure is force per unit area, we can calculate the force by multiplying pressure by the area of the door:
Force = Pressure x Area
= 15288 Pa x 1.04 m2
≈ 15922 N
Therefore, approximately 15922 Newtons of force is required to open the door of the watertight car under the given conditions.