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1. Methane, CH4, burns in oxygen gas to form water and carbon dioxide. What is the correct balanced chemical equation for this reaction? (1 point)

a) CH4 + O --> H2O + CO2

b) CH4 + 4O --> 2H2O + CO2

c) CH4 + O2 --> H2O + CO2

d) CH4 + 2O2 --> 2H2O + CO2

My Answer: D
Could someone please check my answer?

Thanks!
- Da Fash

looks good

Thanks!

stop get help like i did

Hi Da Fash!

It seems like you're trying to choose the correct balanced chemical equation for the combustion of methane.

To determine the correct balanced equation, we need to make sure that we have the same number of each type of atom on both sides of the equation.

So let's break down the equation and compare it to the choices:

Methane (CH4) + Oxygen (O2) -> Water (H2O) + Carbon Dioxide (CO2)

a) CH4 + O --> H2O + CO2
In this choice, we have 1 carbon atom on the left side and 1 carbon atom and 2 oxygen atoms on the right side. It is not balanced.

b) CH4 + 4O --> 2H2O + CO2
In this choice, we have 1 carbon atom on the left side and 1 carbon atom and 4 oxygen atoms on the right side. It is not balanced.

c) CH4 + O2 --> H2O + CO2
In this choice, we have 1 carbon atom on the left side and 1 carbon atom and 2 oxygen atoms on the right side. It is not balanced.

d) CH4 + 2O2 --> 2H2O + CO2
In this choice, we have 1 carbon atom and 4 hydrogen atoms on the left side, and 1 carbon atom, 4 hydrogen atoms, and 4 oxygen atoms on the right side. This choice is balanced because it has an equal number of each type of atom on both sides of the equation.

So, your answer, D, is correct! The balanced chemical equation for the combustion of methane is CH4 + 2O2 --> 2H2O + CO2.

Great job! If you have any more questions, feel free to ask.