A supertanker (mass = 1.57E+8 kg) is moving with a constant velocity. Its engines generate a forward thrust of 7.47E+5 N. Determine the magnitude of the resistive force exerted on the tanker by the water.
Changing screennames won't help. The tutors want to know what YOU THINK. They'll help you but won't solve your problems for you.
Steph & I are in the same physics class and just need help, she's been sick and I'm hella confused, that's all.
None of that matters.
If you don't let the physics tutors know what you do and don't understand about these problems, they can't really help you. It's not that difficult to go back to all previous posts and indicate what you know, where you get stuck, etc.
The velocity is constant so there should be equal opposite forces.
To determine the magnitude of the resistive force exerted on the tanker by the water, we need to use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration. In this case, since the tanker is moving with a constant velocity, its acceleration is zero, which means the net force acting on it must also be zero.
The net force acting on the tanker can be calculated by subtracting the forward thrust generated by the engines from the resistive force exerted by the water:
Net force = Forward thrust - Resistive force
Since the net force is zero, we can set up the following equation:
0 = 7.47E+5 N - Resistive force
Rearranging the equation, we can solve for the resistive force:
Resistive force = 7.47E+5 N
Thus, the magnitude of the resistive force exerted on the tanker by the water is 7.47E+5 N.