physics

Two workers are sliding 450 kg crate across the floor. One worker pushes forward on the crate with a force of 380 N while the other pulls in the same direction with a force of 380 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor?

asked by Zachary
  1. normal force = 450*9.81 = 4414. N
    friction force = 4415 mu
    so
    380 + 380 = 4415 mu

    posted by Damon

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