Earth orbits the sun at an average distance of about 150 million kilometres every 365.2564 mean solar days, or one sidereal year. What is the linear velocity of th3 Earth in kilometres per hour?
R = 1.50* 10^8 km
circumference= 2 pi*1.50*10^8 = 9.42*10^8 km
T =365.2564 * 24 = 8766 hours = 8.766*10^3
so
v = C/T = (9.42/8.766)10^5 = 1.075*10^5
= 107,500 km/hr
what is w*radius?
w=PI*2*r/365 days
convert days to hours (365*24)
Damon, why did you find the circumference when we already have the distance?
The velocity is perpendicular to the radius. It is tangent to the circle which is 2 pi R around.
To find the linear velocity of Earth, we need to determine the distance it travels in one hour. Here's how you can calculate it:
Step 1: Find the distance Earth travels in one day:
We know that Earth orbits the sun at an average distance of about 150 million kilometers every 365.2564 mean solar days. So, the distance Earth travels in one day can be calculated by dividing the total distance by the number of days in a year:
Distance traveled in one day = (150 million km) / (365.2564 days)
Step 2: Convert the distance to kilometers per hour:
To find the linear velocity of Earth in kilometers per hour, we need to calculate the distance traveled in one hour. Since there are 24 hours in a day, we divide the distance traveled in one day by 24:
Distance traveled in one hour = (Distance traveled in one day) / 24
Now, let's calculate the linear velocity of Earth in kilometers per hour:
Distance traveled in one day = (150 million km) / (365.2564 days) ≈ 410,190 km
Distance traveled in one hour = (Distance traveled in one day) / 24 ≈ 17,091.25 km
Therefore, the linear velocity of Earth is approximately 17,091.25 kilometers per hour.