Hello this is my first experiment I've ever done before and it was fun but I gotta figure out what NaCl produced and what it yielded in percentage. Can someone double check my work.
Na2CO3+2HCl=2NaCl+H2O+CO2
Mass of empty crucible & cover: 33.076g
Mass of sodium carbonate used to start experiment: 0.575g Na2CO3
Mass of crucible, cover & sodium chloride after experiment: 33.653g NaCl
My answers:
Sodium Chloride produced: (0.575gNa2CO3/106gNa2CO3) x (2mole NaCl/1moleNaCO3) x 58gNaCl mole = 66.7/106g = 0.629g NACl
--->I used 3 sig figs because the starting amount of sodium chloride was 3 sig figs.<---
Actual mass of NaCl produced: 33.653-33.076= 0.577g NaCl
Percentage yielded: 0.577gNaCl/0.629NaCl= .917 x 100= 92%
Thanks for checking my work.
Your calculations seem generally correct, but there are a few minor errors in your explanation. Let's go through them step by step to verify your work:
1. Sodium Chloride produced:
To calculate the amount of sodium chloride (NaCl) produced, you correctly started by using the molar ratio between sodium carbonate (Na2CO3) and sodium chloride (2NaCl/1Na2CO3). However, there is a typo in the molecular weight of sodium chloride. The correct formula weight for NaCl is 58.5 g/mol, so the calculation should be:
(0.575g Na2CO3) x (2 mol NaCl/1 mol Na2CO3) x (58.5g NaCl/1 mol NaCl) = 0.629g NaCl
You rounded the answer to three significant figures, which is appropriate based on the starting amount of sodium carbonate.
2. Actual mass of NaCl produced:
To find the actual mass of sodium chloride produced, you correctly subtracted the mass of the empty crucible and cover from the mass of the crucible, cover, and sodium chloride after the experiment:
33.653g NaCl - 33.076g = 0.577g NaCl
3. Percentage yield:
To calculate the percentage yield, divide the actual mass of sodium chloride produced by the theoretical mass of sodium chloride you calculated earlier, and then multiply by 100 to convert to a percentage:
(0.577g NaCl / 0.629g NaCl) x 100 = 91.7%
You made a small mistake in your calculation of the percentage yield. It appears that you divided 0.577g NaCl by 0.629g NaCl, which gave you the incorrect result of 0.917. Instead, the correct calculation yields 91.7%.
In summary, the corrected answers are:
- Sodium Chloride produced: 0.629g NaCl
- Actual mass of NaCl produced: 0.577g NaCl
- Percentage yielded: 91.7%
Good job on your first experiment, and keep up the good work in understanding and checking your calculations!