Question

Solution set of sin 2x = -1/2 in [0,2pi)

Answer 1

since sin(π/6) = 1/2

and sine is negative in QII and QIV,
2x = 7π/6 or 11π/6 + 2nπ
x = 7π/12 + nπ or 11π/12 + nπ