H2SO4+2NaOH->2H2O+Na2SO4
How many molecules of water are produced when 12g of sodium sulfate are created?
Is this answer correct:
75Lx6.02^23= 452molecules H2O
moles water=twice moles of sodium sulfate
= 2*12/142
molecules water=moleswater*avag number.
No, your answer is absurd. Avag number is
6.02*10^23
To determine the number of molecules of water produced when 12g of sodium sulfate (Na2SO4) is created, we need to use stoichiometry.
First, we need to find the number of moles of sodium sulfate using its molar mass. The molar mass of Na2SO4 is calculated as follows:
2(Na) + 1(S) + 4(O) = 46 + 32 + (4 * 16) = 142 g/mol
Since 12g of sodium sulfate is given, we can use this information to find the number of moles:
moles = mass / molar mass = 12g / 142 g/mol ≈ 0.0845 mol
Next, we examine the balanced chemical equation for the reaction:
H2SO4 + 2NaOH -> 2H2O + Na2SO4
According to the equation, for every 2 moles of Na2SO4, we will obtain 2 moles of H2O. Therefore, the ratio of moles of water to moles of Na2SO4 is 2:2, which simplifies to 1:1.
So, we have 0.0845 moles of Na2SO4, which means we will obtain an equal number of moles of water. Therefore, the number of moles of water produced is also 0.0845 mol.
Now, to find the number of water molecules, we can use Avogadro's number (6.02 x 10^23 molecules/mol):
number of molecules = number of moles x Avogadro's number
number of molecules = 0.0845 mol x (6.02 x 10^23 molecules/mol) ≈ 5.08 x 10^22 molecules
So, the correct answer is approximately 5.08 x 10^22 molecules of water. Your answer of 452 molecules is incorrect.