physics

A uniform metre rule of mass 90g is pivoted at the 40cm mark. If the rule is in equilibrium with an unknown mass m placed at the 10cm mark and a 72g mass at the 70cm mark,determine m.

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  1. 16

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  2. please show solving
    to the answer ofthis question

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  3. Assume all of the mass of the meter ruler is centered at center of gravity at 50 cm.

    Sum of the torques must be zero

    Pivot is at 40 cm
    Torque due to mass of ruler = 10 * 90 = 900 g cm
    Torque due to 72 g = 30 * 72 = 2160 g cm
    Torque due to M = M * 30 and opposite direction

    30 M = 2160 + 900 = 3060

    M = 102 g

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  5. it's understood now

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  6. How did you get 30 in the solving for torque

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  7. The distance between the point of pivot and the mass is 30cm
    Don't forget perpendicular distance

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