H2SO4+2NaOH->2H2O+Na2SO4
1.) How many grams of H2SO4 are needed to produce 135L of water?
2.) How many molecules of water are produced when 12g of sodium sulfate are created?
H2SO4+2NaOH->2H2O+Na2SO4
2.) How many molecules of water are produced when 12g of sodium sulfate are created?
Appreciate the help. I'm stuck on this one. Thanks!
To answer these questions, we need to use stoichiometry, which relates the various components in a chemical reaction.
1.) To find the number of grams of H2SO4 needed to produce 135L of water, we first need to determine the ratio of moles of H2SO4 to moles of water in the balanced equation. From the equation, we can see that the ratio is 1:2.
1 mole of H2SO4 produces 2 moles of H2O.
Next, we need to convert liters of water to moles using the ideal gas law, assuming standard conditions of temperature and pressure. The molar volume of an ideal gas at STP (standard temperature and pressure) is approximately 22.4L/mol.
135L of water is equal to:
135L / 22.4L/mol = 6.026 moles of water
Since the ratio of H2SO4 to H2O is 1:2, we need half the number of moles of H2SO4. Therefore, we need:
6.026 moles / 2 = 3.013 moles of H2SO4
Finally, we can calculate the grams of H2SO4 needed by multiplying the moles by the molar mass. The molar mass of H2SO4 is:
2(1g/mol H) + 32.1g/mol S + 4(16g/mol O) = 98.1g/mol H2SO4
So, the mass of H2SO4 needed is:
3.013 moles * 98.1g/mol = 295.51 grams of H2SO4
Therefore, approximately 295.51 grams of H2SO4 are needed to produce 135L of water.
2.) To find the number of molecules of water produced when 12g of sodium sulfate (Na2SO4) are formed, we need to use the molar mass and Avogadro's number.
First, we calculate the number of moles of Na2SO4:
12g Na2SO4 / (142.04g/mol Na2SO4) = 0.0846 moles Na2SO4
From the balanced equation, we know that 1 mole of Na2SO4 produces 2 moles of H2O. Therefore, we have:
0.0846 moles Na2SO4 * 2 moles H2O / 1 mole Na2SO4 = 0.1692 moles H2O
Next, we use Avogadro's number, which tells us the number of molecules in one mole of substance. Avogadro's number is approximately 6.022 x 10^23 molecules/mol.
0.1692 moles H2O * (6.022 x 10^23 molecules/mol) = 1.018 x 10^23 molecules
Therefore, approximately 1.018 x 10^23 molecules of water are produced when 12g of sodium sulfate (Na2SO4) are created.