H2SO4+2NaOH->2H2O+Na2SO4

1.) How many grams of H2SO4 are needed to produce 135L of water?

2.) How many molecules of water are produced when 12g of sodium sulfate are created?

how many moles of H2O in 135L (at 18g/mole)?

half that many moles of H2SO4

Now use Avogadro's Number to find # molecules.

So is this right?

1.) 18g H2SO4. If so why wouldn’t we include Sulfur?

2.) 108x6.02^23= 108molecules H2O

Thanks for the help.

To answer your questions, we need to use the balanced chemical equation:

H2SO4 + 2NaOH -> 2H2O + Na2SO4

1.) To determine the grams of H2SO4 needed to produce 135L of water, we will use the molar ratio from the balanced equation.

From the equation, we can see that 1 mole of H2SO4 produces 2 moles of H2O. To calculate the moles of water, we need to convert liters to moles using the molar volume of an ideal gas at standard temperature and pressure (STP).

The molar volume of an ideal gas at STP is approximately 22.4 L/mol.

135 L of water = (135 L) / (22.4 L/mol) ≈ 6.03 mol of water

Since 1 mole of H2SO4 produces 2 moles of H2O, we can conclude that 6.03 mol of water requires half that amount of H2SO4.

Therefore, 6.03 mol of water requires (6.03 mol) / 2 ≈ 3.02 mol of H2SO4.

To determine the mass of H2SO4 needed, we need to use the molar mass of H2SO4, which is approximately 98.09 g/mol.

Mass of H2SO4 = (3.02 mol) × (98.09 g/mol) ≈ 296.17 g

Therefore, approximately 296.17 grams of H2SO4 are needed to produce 135 liters of water.

2.) To determine the number of molecules of water produced when 12g of sodium sulfate (Na2SO4) is created, we need to use the molar mass and Avogadro's number.

The molar mass of Na2SO4 is approximately 142.04 g/mol.

To calculate the number of moles of Na2SO4, we use the relationship:

Moles of Na2SO4 = Mass / Molar mass = 12g / 142.04 g/mol ≈ 0.0845 mol

From the balanced equation, we know that 1 mole of Na2SO4 produces 2 moles of H2O.

Therefore, the moles of H2O produced will be twice the moles of Na2SO4:

Moles of H2O = 2 × 0.0845 mol ≈ 0.169 mol

Now, we need to convert the moles of water to molecules.

Using Avogadro's number (6.022 x 10^23 molecules/mol), we can calculate:

Number of water molecules = Moles of H2O × Avogadro's number

Number of water molecules = 0.169 mol × 6.022 × 10^23 molecules/mol ≈ 1.02 × 10^23 molecules

Therefore, approximately 1.02 × 10^23 molecules of water are produced when 12g of sodium sulfate is created.

To solve these questions, we need to use stoichiometry, which is the calculation of the quantities of reactants and products in a chemical reaction.

1.) To find the grams of H2SO4 needed to produce 135L of water, we need to use the balanced chemical equation:
H2SO4 + 2NaOH -> 2H2O + Na2SO4

The equation shows that for every 2 moles of NaOH, 2 moles of H2O are produced. Therefore, we need to find the moles of water produced.

The molar volume of any gas at standard temperature and pressure (STP) is 22.4L/mol. Since water is a liquid, we need to convert liters to moles by dividing by the molar volume:
135L / 22.4 L/mol = 6.03 moles of water

According to the balanced equation, 2 moles of water are formed from 1 mole of H2SO4. Therefore, to determine the moles of H2SO4 needed, we need to use the stoichiometric ratio:
6.03 moles of water * (1 mole of H2SO4 / 2 moles of H2O) = 3.02 moles of H2SO4

To convert moles of H2SO4 to grams, we need to know the molar mass of H2SO4. The molar mass of H2SO4 is:
2(1g/mol of H) + 32g/mol of S + 4(16g/mol of O) = 98g/mol

So, to find the grams of H2SO4 needed, we multiply the moles of H2SO4 by its molar mass:
3.02 moles of H2SO4 * (98g/mol) = 296g of H2SO4

Therefore, 296 grams of H2SO4 are needed to produce 135L of water.

2.) To find the number of molecules of water produced when 12g of sodium sulfate (Na2SO4) is created, we need to use the balanced chemical equation:
H2SO4 + 2NaOH -> 2H2O + Na2SO4

The equation shows that for every 1 mole of Na2SO4 produced, 2 moles of water are produced. Therefore, we need to find the moles of water formed.

First, we need to determine the moles of Na2SO4 using its molar mass. The molar mass of Na2SO4 is:
2(23g/mol of Na) + 32g/mol of S + 4(16g/mol of O) = 142g/mol

To find the moles of Na2SO4, we divide the given mass by its molar mass:
12g / 142g/mol = 0.0845 mol of Na2SO4

According to the balanced equation, 2 moles of water are formed from 1 mole of Na2SO4. Therefore, to determine the moles of water produced, we need to use the stoichiometric ratio:
0.0845 mol of Na2SO4 * (2 moles of H2O / 1 mole of Na2SO4) = 0.169 moles of H2O

Finally, to determine the number of water molecules, we use Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 molecules. Therefore, we can convert moles of water to molecules using the formula:
0.169 moles of H2O * (6.022 x 10^23 molecules / 1 mole) = 1.02 x 10^23 molecules of H2O

Therefore, when 12g of sodium sulfate is created, approximately 1.02 x 10^23 molecules of water are produced.