In planning for retirement, Karen deposits some money at 2.5% interest and deposits

twice as much at 3% interest. Find the amount of money invested at each rate if the total
annual income from interest is $850.

Rachel/Faith -- please use the same name for your posts.

Also -- you might get a response if you posted your ideas about the problem.

Otherwise it looks like you want to be a cheater and have someone else give you the answers.

If Karen deposits $x in the 2.5% account, how much does she deposit in the other account ??

if her interest from the first account is .025x , what is ther interest from the 2nd account ??

(sum of the two interests) = 850

take over

To find the amount of money invested at each rate, we can set up a system of equations based on the given information.

Let's represent the amount of money invested at 2.5% interest as 'x' and the amount invested at 3% interest as '2x' (since it is twice as much).

The annual income from the 2.5% interest is calculated as 0.025x (2.5% is equivalent to 0.025 in decimal form).

The annual income from the 3% interest is calculated as 0.03(2x) = 0.06x (since this amount is twice as much as the amount invested at the 2.5% interest rate).

The total annual income from interest is given as $850, so we can set up the following equation:

0.025x + 0.06x = 850

Combining like terms:

0.085x = 850

Dividing both sides of the equation by 0.085:

x = 850 / 0.085

x ≈ 10,000

Therefore, Karen invested approximately $10,000 at the 2.5% interest rate, and twice that amount ($20,000) at the 3% interest rate.