How do you find the max height of a projectile given the angle and Vi?
Angle = 57.0 degrees
Initial V = 46 m/s
The max height is a function of the vertical velocity and gravity. At the top (max height), VERTICAL velocity is zero.
Vtop=Vi-gt
0=46Sin57 -9.8*time
solve for time.
Then
h=Vi*t0-1/2 g t^2 put time in, and you have h max.