Chemistry

Calculate the number of moles of calcium chloride Cacl2 that can be obtained from 25g of limestone CaCo3 in the presence of excess hydrogen chloride

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  1. same as moles of CaCO3

    CaCO3 = 100 g/mol = 40 + 12 + 48
    so we have 0.25 mols of lime and will get 0.25 mols of CaCl2

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  2. 0.25 moles of cacl2 as:
    CaCo3+ HCl = CaCl2 + H2CO3
    SO 1 mol of CaCO3 will give 1 mol of CaCl2.
    mass of CaCO3= 25g
    Molar mass of CaCO3= 100g
    therefore moles of CaCO3 = 25/100 =0.25
    thus 0.25 moles of CaCl2 will be produced

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  3. Calculate the number of moles of calcium chloride (Cacl2) that can be obtained from 25g of limestone (Caco3) in the presence of excess hydrogen chloride (HCl)

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  4. I don't know how to

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  5. yes

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  6. I don't understand

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  7. Calculate the number of mole of calium chride cacl2 that can be obtaibed from 25g of lime stone. Caco3 in the present of excess of hydrogen chloride hcl (ca 40, (12,o 16, h 1 cl (355)

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  8. Calculate the number of moles of calcium chloride CaCl2 that can be obtained from the 20g linestone CaC3 in the presence of excess hydrogen chloride (Can=40,it=1,C=12 O = 16 ,Cl=35.5)

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  9. Mass of caco3

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  10. I don't know how to get it

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  11. oyes i know how

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  12. I don't understand how to solve it

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  13. I don't understand how to solve it

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  14. Caco3 +2Hcl(aq)=cacl2+h2o (l)+co2(g)

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