Hi there is somebody can help me to understand the problem and how to do it? Thank you

h(n) = n^2 + 4n
g(n) = 4n + 2
Find (h + 4g)(6)

Tank you again for help me

n^2 + 4 n + 16 n + 8

n^2 + 20 n + 8

36 + 120 + 8

Thank you so much Damon.

Of course, I can help you understand the problem and how to solve it!

To find the value of (h + 4g)(6), we need to substitute 6 into the expressions for h and g, and then perform the given operations.

Let's start by finding the value of h(6). The function h(n) is defined as h(n) = n^2 + 4n. To find h(6), we substitute 6 into the equation:
h(6) = (6)^2 + 4(6)
= 36 + 24
= 60

Next, let's find the value of g(6). The function g(n) is defined as g(n) = 4n + 2. Substituting 6 into the equation, we get:
g(6) = 4(6) + 2
= 24 + 2
= 26

Now, we can calculate (h + 4g)(6) by substituting the values of h(6) and g(6) into the expression:
(h + 4g)(6) = h(6) + 4 * g(6)
= 60 + 4 * 26
= 60 + 104
= 164

Therefore, the value of (h + 4g)(6) is 164.

To summarize the steps:
1. Evaluate h(n) by substituting n = 6 into the equation h(n) = n^2 + 4n.
2. Evaluate g(n) by substituting n = 6 into the equation g(n) = 4n + 2.
3. Substitute the calculated values of h(6) and g(6) into the expression (h + 4g)(6).
4. Calculate the result to find the final answer, which is 164.

I hope this explanation helps you understand the problem and how to solve it! Let me know if you have any further questions.