If a 2.0-kilogram mass is raised 0.050 meter vertically, the work done on the mass is approximately

(1) 0.10 J
(2) 0.98 J
(3) 9.8 J
(4) 40. J

So what is the answer!?

To calculate the work done on an object, you need to use the formula:

Work = force × distance × cos(θ)

In this case, since the mass is being raised vertically, the angle between the applied force and the direction of motion is 0 degrees. Therefore, the cosine of 0 degrees is 1, so we don't need to consider the angle in our calculation.

The force required to lift an object vertically is equal to its weight, which can be calculated using the formula:

Weight = mass × acceleration due to gravity

The acceleration due to gravity is approximately 9.8 m/s² on the surface of the Earth.

Let's plug in the values:

Mass = 2.0 kg
Distance = 0.050 m
Acceleration due to gravity = 9.8 m/s²

Weight = mass × acceleration due to gravity
Weight = 2.0 kg × 9.8 m/s² = 19.6 N

Now, we can calculate the work done:

Work = force × distance = Weight × distance
Work = 19.6 N × 0.050 m = 0.98 J

Therefore, the work done on the mass is approximately 0.98 J.

So the correct answer is (2) 0.98 J.

Isnt work done equal to weight times distance?

Think about the units of work

work=force*distance
joule=newton*meter

a joule is N-m

ok thanks a lot. I appreciate it =)

The answer is 1

yes. the book says work = force times direction of displacemnt. but im confused about the joules unit. According to this review book, 1 newton * meter = 1 kilogram * meter squared/second squred = 1 joule. Would it be 0.1 joules? Or is it 0.1 newton*meters and i would have to convert it?