The population of a town increases at the rate of 40 per thousand. Its population after 2 years will be 6084. Find its present population
6084 = x e^(2 * .04)
ln(6084) = ln(x) + .08
To solve this problem, we need to use the concept of population growth rate and the formula for calculating population increase.
Let's denote the present population of the town as P.
We know that the population increases at a rate of 40 per thousand. This means that every year, the population increases by 40/1000 of the current population.
After 2 years, the population will have increased by (2 * 40/1000) = 80/1000 = 0.08 times the present population.
Now, we can set up an equation to solve for the present population:
P + 0.08P = 6084
Simplifying the equation, we have:
1.08P = 6084
Dividing both sides of the equation by 1.08:
P = 6084 / 1.08
Using a calculator, we find that P is approximately 5644.44.
Therefore, the present population of the town is approximately 5644.44.