two busses both leave from the same station the blue line leaves every 15 minutes and the red line leaves every 20 minutes if both busses leave the station at 9:15 AM what time will it be when both busses leave at the same time again

The least common multiple of 15 and 20 is 60. Take it from there.

Here is your answer

Take out the LCM
SO first DO THE PRIME FACTORISATION OF 10,15 and 24

10=2×5
15= 3×5
24=2×2×2×3

LCM= 2×2×2×3×5
=120min

Trian will depart on all three lines at the same time after every 120 minutes or 2hours

Need help right now

60 is the least common multiple of 15 and 20 so 9:15 plus an hour is = to 10:15.

To find out when both buses will leave the station at the same time again, you need to determine the least common multiple (LCM) of 15 and 20. The LCM is the smallest positive integer that is divisible by both numbers.

First, find the factors of each number:
15: 1, 3, 5, 15
20: 1, 2, 4, 5, 10, 20

Identify the common factors:
15: 1, 5
20: 1, 4, 5

The common factors are 1 and 5. To calculate the LCM, you multiply the common factors and any remaining factors:
LCM = 1 * 5 * 4 = 20

Therefore, the buses will leave the station at the same time every 20 minutes. Since they both left at 9:15 AM, the next time they will leave together is 20 minutes later, at 9:35 AM.

They will both leave at 10:00