I definately do not understand this problem.

If y varies directly with x, and y = 600 when x = 1000, find the constant of variation K.

If y is directonally (proportional) to x, then for every value of x there is a value for y multiplied by a constant value. So if was that we had for every value of x the value of y was three time x; then if x = 4, y=12; if x=6, y=18; if x=10,y=30 and so on. So we have an equation y=3x (y=Kx) and K would equal 3.

So for y=Kx

you have been given values for x and y in the question, you can find K.

K = Y/X = 600/1000 = 0.6

Y/X = 0.6
Y = 0.6x
Y = kx

To find the constant of variation (K), you need to use the given values for x and y in the equation y = Kx.

In this case, y = 600 when x = 1000.

Substituting these values into the equation, we get:

600 = K * 1000

To solve for K, divide both sides of the equation by 1000:

600/1000 = K

Simplifying, we get:

K = 0.6

So, the constant of variation (K) is 0.6 in this case.

Therefore, the equation relating y and x is y = 0.6x.