Michael wants to rent a car on his vacation. The rental fee is 60 dollars per day plus a refueling charge of $40. He has at most 400.00 to spend. The inequality 60d +40 <= 400 can be used to find d, the number of days he can rent the car. Solve the inequality and interpret the solution. I got
d <=6 , no more than 6 days, then if he upgraded to a car with a daily rental of 75.00 dollars ...75d +40 <=400
I got:
d <= 4.8
so is the answer he can rent the car for 4 or less days?
sorry and thank you so much
Yes, both your answers are correct. :-)
To solve the inequality 60d + 40 <= 400, where d represents the number of days Michael can rent the car, we need to isolate d on one side of the inequality.
First, subtract 40 from both sides of the inequality to get: 60d <= 360.
Next, divide both sides of the inequality by 60 to solve for d: d <= 6.
So, Michael can rent the car for 6 days or less according to the first inequality.
Now, if he wants to upgrade to a car with a daily rental of $75, we need to solve the inequality 75d + 40 <= 400.
Subtract 40 from both sides: 75d <= 360.
Divide both sides by 75: d <= 4.8.
Since we cannot have a fraction of a day, we round down to the nearest whole number.
Therefore, according to the second inequality, Michael can rent the upgraded car for 4 days or less.
In conclusion, if Michael wants to rent the car without an upgrade, he can rent it for 6 days or less. However, if he wants to upgrade to a car with a daily rental of $75, he can only rent it for 4 days or less.