Martin is making a candy that contains 90% milk chocolate and the rest caramels. The candy has 3 pounds of caramels.
Part A: Write an equation using one variable that can be used to find the total number of pounds of milk chocolate and caramels in the candy. Define the variable used in the equation.
Part B: How many pounds of milk chocolate are present in the candy? Show your work.
Is this right?: Total amount of chocolate will be p.
The amount of caramel=3 pounds;
The amount of milk=90%=0.9/0.1*3=27 pounds milk
Therefore the total amount of milk in candy will be:
m=0.9p
The total amount of caramel will be:
c=0.9p
Percentage of Caramel in chocolate is 10%. The amount of milk will therefore be:
0.9/0.1*3=27 pounds
Let the total amount of candy be x lbs
So .9x is milk chocolate
and .1x is caramel
but .1x = 3
x = 3/.1 = 30 lbs
So the total amount of candy is 30 lbs, with
90% of 30 or 27 lbs of chocolate, and
10% of 30 or 3 lbs of caramel
The question said to use one variable, I see you used m, p, and c .
Please help me!
Could someone verify my answer please?
27 pounds is right.
The rest isn't right?
Part A:
Let's define the variable used in the equation as "p", which represents the total number of pounds of milk chocolate and caramels in the candy.
We know that the candy contains 90% milk chocolate and the rest caramels, which means the percentage of caramels is 10%. The equation that can be used to find the total number of pounds of milk chocolate and caramels in the candy is:
p = pounds of milk chocolate + pounds of caramels
Part B:
Given that the candy has 3 pounds of caramels, we can substitute this value into the equation from Part A:
p = pounds of milk chocolate + 3
We also know that the candy is 90% milk chocolate, which means the percentage of milk chocolate is 90%. We can represent this as 0.9 in decimal form. To find the pounds of milk chocolate, we can multiply the total number of pounds (p) by 0.9:
pounds of milk chocolate = 0.9 * p
Substituting the value of 0.9p for pounds of milk chocolate in the equation, we have:
p = 0.9p + 3
To solve for p, we can subtract 0.9p from both sides of the equation:
p - 0.9p = 3
Simplifying the equation, we have:
0.1p = 3
To isolate p, we can divide both sides of the equation by 0.1:
p = 3 / 0.1
Therefore, the total number of pounds of milk chocolate and caramels in the candy is 30 pounds.
To find the pounds of milk chocolate, we can substitute the value of p into the equation we derived earlier:
pounds of milk chocolate = 0.9 * p
pounds of milk chocolate = 0.9 * 30
pounds of milk chocolate = 27
So, there are 27 pounds of milk chocolate present in the candy.