Hi, if anyone can help me with this problem I would greatly appreciate it. I understood all my other math problems except for this one. So if anyone could help walk me through the steps so I know for next time how to solve problems like this I would appreciate it :D.

1.Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(2,-2);y=-x-2
A.y=-2x
B.y=2x
C.y=1/2x
D.y=-x

parallel to y = -1 x -2

has slope of -1
so of form
y = -1 x + b
now get b from that point.(2,-2)
-2 = -1(2) + b
-2 =-2 + b
b = 0
so
y = -x

Oh that makes senses now ,thank you for the help :)

Of course, I'd be happy to help you with this math problem!

To write an equation in slope-intercept form of the line that is parallel to the given equation and passes through the point (2, -2), we need to understand some key concepts.

The slope-intercept form of a linear equation is given by y = mx + b, where m represents the slope of the line, and b represents the y-intercept (the point where the line intersects the y-axis).

Since the line we're looking for is parallel to the given equation, it means that they have the same slope. Therefore, we need to find the slope of the given equation y = -x - 2.

In this equation, the coefficient of x (-1) represents the slope. So, the slope of the given line is -1.

Now we have the slope (-1) and the point (2, -2). We can use the point-slope form of a linear equation which is given by y - y1 = m(x - x1). In this equation, (x1, y1) represents any point on the line, and m represents the slope.

Substituting the values into the point-slope form, we get:

y - (-2) = -1(x - 2)
y + 2 = -1(x - 2)
y + 2 = -x + 2

Now, we'll rearrange the equation to get it in slope-intercept form:

y = -x + 2 - 2
y = -x

Therefore, the equation in slope-intercept form for the line that is parallel to the given equation and passes through the point (2, -2) is:

D. y = -x