A rail gun uses electromagnetic energy to accelerate objects quickly over a short distance. In an experiment, a 2.00 kg projectile remains on the rails of the gun for only 3.500e-2 s, but in that time it goes from rest to a velocity of 4.00×103 m/s. What is the average acceleration of the projectile?

vf=vi+a*t

solve for a

a=vf/time

To find the average acceleration of the projectile, we can use the equation:

average acceleration = (final velocity - initial velocity) / time

Given:
Mass of the projectile (m) = 2.00 kg
Time (t) = 3.500e-2 s
Final velocity (v_f) = 4.00 × 10^3 m/s
Initial velocity (v_i) = 0 m/s (since the projectile starts from rest)

Using the given values in the equation, we can calculate the average acceleration:

average acceleration = (4.00 × 10^3 m/s - 0 m/s) / 3.500e-2 s
average acceleration = (4.00 × 10^3 m/s) / 3.500e-2 s

Now, let's solve for the average acceleration:

average acceleration = 1.14 × 10^5 m/s^2

Therefore, the average acceleration of the projectile is 1.14 × 10^5 m/s^2.

To calculate the average acceleration of the projectile, we can use the formula:

acceleration = (final velocity - initial velocity) / time

Given:
- Mass of the projectile, m = 2.00 kg
- Initial velocity, u = 0 m/s (since the projectile starts from rest)
- Final velocity, v = 4.00 × 10^3 m/s
- Time, t = 3.500e-2 s

Substituting the values into the acceleration formula:

acceleration = (4.00 × 10^3 m/s - 0 m/s) / (3.500e-2 s)

Now, let's calculate the average acceleration.

acceleration = 4.00 × 10^3 m/s / 3.500e-2 s
acceleration = 1.14 × 10^5 m/s^2

Therefore, the average acceleration of the projectile is 1.14 × 10^5 m/s^2.

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