6ab^2-(q-r)^2

and what do you need help with?

Factoring....

6(ab)2

Do you mean the original question should have been to factor

6(ab)^2-(q-r)^2 ?

That is the difference of two squares.

Follow the appropriate procedure.

what procedure?

For any quantities A and B

A^2 - B^2 = (A+B)(A-B)

In your case, let A = ab*sqrt6 and B = (q-r)
then write down the two factors in terms of a, b, q and r

i need help On graphing