A car weighing 1000kg is on slope that makes an angle 30° with the horizontal.the component of car's weight parallel to the slope is(g=10)
m g sin 30 = 1000 * 10 * 0.5
To find the component of the car's weight parallel to the slope, we need to consider the gravitational force acting on the car.
The weight of an object can be calculated using the formula:
Weight = mass × acceleration due to gravity
Given that the weight of the car is the force acting vertically downward, and the angle of the slope is given as 30°, we need to find the component of the weight that acts parallel to the slope.
To do this, we can break down the weight vector into its horizontal and vertical components using trigonometry.
The component of the weight parallel to the slope is given by:
Weight parallel to slope = Weight × sin(angle of slope)
Given that the weight of the car is equal to its mass multiplied by the acceleration due to gravity (g), we can substitute the values into the equation:
Weight parallel to slope = (mass × g) × sin(angle of slope)
Plugging in the given values, where mass = 1000 kg and g = 10 m/s^2, and the angle of slope is 30 degrees:
Weight parallel to slope = (1000 kg × 10 m/s^2) × sin(30°)
Now, we can calculate the value:
Weight parallel to slope = (10,000 kg⋅m/s^2) × 0.5
Weight parallel to slope = 5,000 kg⋅m/s^2
Therefore, the component of the car's weight parallel to the slope is 5,000 kg⋅m/s^2.