An electron is acted upon by a force of 3.50×10−15 N due to an electric field. Find the acceleration this force produces in each case:
The electron's speed is 6.00 km/s . =3.84*10^15
The electron's speed is 2.60×108 m/s and the force is parallel to the velocity. unsure how to get the answer for second question
To find the acceleration produced by the force acting on the electron, you can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula can be written as:
acceleration = net force / mass
For the first case, where the electron's speed is 6.00 km/s and the force is given as 3.50×10−15 N, you also need to know the mass of the electron. The mass of an electron is approximately 9.11×10−31 kg.
To get the acceleration in this case, you can use the formula:
acceleration = (3.50×10−15 N) / (9.11×10−31 kg)
Plugging in the values:
acceleration = 3.50×10−15 N / 9.11×10−31 kg
≈ 3.84×10^15 m/s²
So the acceleration produced by the force in the first case is approximately 3.84×10^15 m/s².
Now let's move on to the second case, where the electron's speed is 2.60×10^8 m/s and the force is parallel to the velocity. In this case, the net force is equal to the electric field force applied on the electron.
Since the force is parallel to the velocity, the work done by the force is zero. According to the work-energy principle, the change in kinetic energy of the electron is equal to the work done on it by the force. Therefore, the electric field force does not change the electron's speed, and the acceleration produced is zero.
Therefore, the acceleration produced by the force in the second case is 0 m/s².