If I was to react a borax solution with a sulphuric acid to neutralise it, what products will I get?
If we include the water of hydration, the unbalanced chemical reaction becomes:
Na2B4O7.11H2O + H2SO4 = H3BO3 + Na2SO4 + H2O
(The coefficient of H2O on the right side is 6. You can finish balancing it to convince yourself it is a viable chemical equation)
Probably boric acid, H3BO3. But if you use concentrated H2SO4 for the acid, you also will get a lot of heat due to the heat of hydration of the acid, itself; so much so that the acid hydration reaction will overwhelm the boric acid formation, especially if you have a relatively weak solution of the borax.
DrBob gave you a good start. Here is a little more information in the form of an unbalanced chemical equation:
Na2B4O7 + H2SO4 + H2O = H3BO3 + Na2SO4
To determine the products of a reaction between borax (sodium borate) and sulfuric acid (H2SO4) to neutralize it, you need to understand the chemical reaction that takes place.
Borax is a salt composed of sodium ions (Na+) and borate ions (B4O7^-2), while sulfuric acid is a strong acid composed of hydrogen ions (H+) and sulfate ions (SO4^-2). When the two react, an acid-base reaction occurs.
The balanced equation for the reaction between borax and sulfuric acid can be represented as follows:
Na2B4O7 + H2SO4 → 2NaHSO4 + B4O7 + H2O
In this reaction, each sodium borate unit (Na2B4O7) combines with two molecules of sulfuric acid (H2SO4) to produce two molecules of sodium bisulfate (NaHSO4), one molecule of tetraborate (B4O7), and one molecule of water (H2O).
Therefore, the products of the reaction between borax solution and sulfuric acid are sodium bisulfate, tetraborate, and water.