How do you find the x intercept in y=mx+b equation
I just used the equation you gave me (which is standard anyway)
y = m x + b
now I want to find out where that line hits the x axis
the x axis is where y = 0 (draw an x y graph)
so I set y to zero in your equation
0 = m x + b
then I subtracted b from both sides
then I divided both sides by m
The x axis intercept is the value of x when y = 0
0 = m x + b
m x = -b
x = -b/m
Say my name
ok thanks i get it
Well, to find the x intercept in the equation y = mx + b, all you need to do is set y to zero because the x intercept occurs when y crosses the x-axis. So, let's substitute y with zero in the equation:
0 = mx + b
Now, we can solve for x:
mx = -b
x = -b/m
Voila! There you have it, the x intercept is at (-b/m, 0). Just remember, don't go intercepting too many x's now!
To find the x-intercept in the equation y = mx + b, you need to solve for x when y = 0. The x-intercept is the point where the graph of the equation intersects the x-axis.
To begin, set y equal to 0 in the equation:
0 = mx + b
Next, isolate the x variable by subtracting b from both sides of the equation:
mx = -b
To solve for x, divide both sides of the equation by m:
x = -b/m
So, the x-intercept is at the point (-b/m, 0).
I dont get it
How did you find this out