How much kcl in grams is contained in 0.488l of 1.25m kcl solution?
First How many mols?
1.25 Mols/Liter * 0.488 Liters = 0.610 Mol
KCl = 39+35.5 = 74.5 grams/mol
0.610 * 74.5 = 45.4 grams
Oh, the "KCl" might stand for "Kindness and Clowning Levels" because that's what I'm all about! But I think in this case, "KCl" actually refers to potassium chloride. Now, let's calculate the amount of KCl in grams in your solution!
To do that, we'll first need to determine the number of moles of KCl in 0.488 liters of a 1.25 M (molar) solution. The formula to calculate the number of moles is:
moles = volume (in liters) × molarity
So, moles = 0.488 L × 1.25 mol/L
Multiplying these values gives us 0.61 moles of KCl.
Now, to convert moles to grams, we need to multiply the number of moles by the molar mass of KCl, which is approximately 74.55 g/mol.
Therefore, grams = 0.61 moles × 74.55 g/mol
Calculating this out, we find that there are approximately 45.49 grams of KCl in the given solution.
Hope that helped, and remember to always approach chemistry with a good sense of humor!
To find the amount of KCl in grams contained in 0.488L of a 1.25M KCl solution, you need to use the formula:
Amount of KCl (in grams) = Volume of solution (in liters) × Molarity × Molar mass of KCl
First, let's calculate the amount of KCl (in moles) using the volume of the solution and the molarity.
Amount of KCl (in moles) = Volume of solution (in liters) × Molarity
Amount of KCl (in moles) = 0.488L × 1.25M
Amount of KCl (in moles) = 0.61 moles
Next, we need to calculate the molar mass of KCl, which is the sum of the atomic masses of potassium (K) and chlorine (Cl).
Molar mass of KCl = Atomic mass of K + Atomic mass of Cl
Molar mass of KCl = 39.10 g/mol + 35.45 g/mol
Molar mass of KCl = 74.55 g/mol
Now, we can calculate the amount of KCl in grams.
Amount of KCl (in grams) = Amount of KCl (in moles) × Molar mass of KCl
Amount of KCl (in grams) = 0.61 moles × 74.55 g/mol
Amount of KCl (in grams) = 45.41 grams
Therefore, there are approximately 45.41 grams of KCl in 0.488L of 1.25M KCl solution.
To find the amount of KCl (Potassium Chloride) in grams contained in the solution, we need to use the given information and some basic calculations.
Let's break down the question step by step:
Step 1: Identify the given information:
- The volume of the solution is 0.488 L.
- The concentration of the KCl solution is 1.25 M.
Step 2: Define what Molarity (M) means:
Molarity is a measure of the concentration of a solute in a solution. It represents the number of moles of solute present in one liter of the solution.
Step 3: Convert the given volume to liters:
0.488 L is already in liters, so we don't need to make any conversions.
Step 4: Calculate the amount of KCl in moles:
Molarity (M) = moles of solute / liters of solution
Rearrange the formula:
moles of solute = Molarity (M) x liters of solution
moles of KCl = 1.25 M x 0.488 L
Step 5: Calculate the amount of KCl in grams:
To convert moles of KCl to grams, we need to use the molar mass of KCl. The molar mass of KCl is 74.55 g/mol (39.10 g/mol for K + 35.45 g/mol for Cl).
moles of KCl x molar mass of KCl = grams of KCl
grams of KCl = (moles of KCl) x (molar mass of KCl)
Now let's calculate:
grams of KCl = (1.25 M x 0.488 L) x 74.55 g/mol
Using a calculator, the final answer is approximately:
grams of KCl = 45.44 grams
Therefore, there are approximately 45.44 grams of KCl in 0.488 liters of a 1.25 M KCl solution.