Chemistry

Hope you don't mind I have
3 more that I don't understand

1)Draw the structure of the reaction product of 2-methyl-1pentene with H2 in the presence od platinum catalyst

2)Draw the structure of
4-methylcyclohexanol

3)Draw the structure of
2,3-dibromotoluene


1)Draw the structure of the reaction product of 2-methyl-1pentene with H2 in the presence od platinum catalyst
These are tough to do. The pentene will be C=C-C-C-C with H atoms attached to each carbon to make four bonds. On carbon #2, the second C from the left most C in the molecule, replace one of the H atoms with a CH3 group. When the double bond is hydrogenated, just add a H atom to each of the C atoms with the double bond and replace the double bond with a single bond. But you don't say if the CH3 group is cis or trans.

2)Draw the structure of
4-methylcyclohexanol
Draw a 6 cornered box much like the cyclopentane I did earlier. Then add H atoms to each to make each C atom have four bonds. Now replace one of the H atoms on one of the C atoms with an -OH group. That will be C abom #1. Then count around the box to C atom #4 and replace one of the H atoms with a -CH3 group.

3)Draw the structure of
2,3-dibromotoluene
Draw a benzene ring with alternationg double bonds and a H attached to each C atom. On the top C atom, place a -CH3 group. That is the methyl group that makes it tolune. That is C atom #1. Then count to 2 and 3 and replace a H on each of the C atoms with Br atoms to make the dibromide.

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asked by Kellie

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