Hope you don't mind I have
3 more that I don't understand
1)Draw the structure of the reaction product of 2-methyl-1pentene with H2 in the presence od platinum catalyst
2)Draw the structure of
4-methylcyclohexanol
3)Draw the structure of
2,3-dibromotoluene
1)Draw the structure of the reaction product of 2-methyl-1pentene with H2 in the presence od platinum catalyst
These are tough to do. The pentene will be C=C-C-C-C with H atoms attached to each carbon to make four bonds. On carbon #2, the second C from the left most C in the molecule, replace one of the H atoms with a CH3 group. When the double bond is hydrogenated, just add a H atom to each of the C atoms with the double bond and replace the double bond with a single bond. But you don't say if the CH3 group is cis or trans.
2)Draw the structure of
4-methylcyclohexanol
Draw a 6 cornered box much like the cyclopentane I did earlier. Then add H atoms to each to make each C atom have four bonds. Now replace one of the H atoms on one of the C atoms with an -OH group. That will be C abom #1. Then count around the box to C atom #4 and replace one of the H atoms with a -CH3 group.
3)Draw the structure of
2,3-dibromotoluene
Draw a benzene ring with alternationg double bonds and a H attached to each C atom. On the top C atom, place a -CH3 group. That is the methyl group that makes it tolune. That is C atom #1. Then count to 2 and 3 and replace a H on each of the C atoms with Br atoms to make the dibromide.
1) To draw the structure of the reaction product of 2-methyl-1pentene with H2 in the presence of a platinum catalyst, start by drawing the structure of 2-methyl-1pentene. This molecule has a chain of five carbon atoms with a double bond between the second and third carbon atoms. Attach hydrogen atoms to each carbon atom to satisfy their valencies.
Next, consider hydrogenation of the double bond using H2 in the presence of a platinum catalyst. Hydrogenation involves adding H atoms to the carbons with the double bond and converting it into a single bond. Add a hydrogen atom to each of the carbon atoms with the double bond and remove the double bond.
It's important to note that you haven't specified whether the CH3 group on carbon #2 is in a cis or trans configuration. The cis form involves the methyl group and the hydrogen atoms on the same side of the double bond, while the trans form involves the methyl group and the hydrogen atoms on opposite sides of the double bond. Without this information, I can't give you a definitive structure for the reaction product.