A person watching the race noticed that at exactly 10:05 am a ant wandered onto the snails 94-cm mark, and reached the 50-cm mark at exactly 10:06 am. What was the velocity of the ant?
Is the answer 44 cm? Because v= d/t
time is 60 sec (1 min)
it went .44 meters (or 6cm)
velocity=.44/60 m/s= 0.0073m/s
or = 44cm/60sec=.73 cm/s
Thanks idk what I did b/c I was way off
To calculate the velocity of the ant, you can use the formula: velocity (v) equals distance (d) divided by time (t).
Here, the distance the ant traveled is 50 cm, and the time it took to cover that distance is 1 minute (from 10:05 am to 10:06 am).
Therefore, the velocity of the ant would be:
v = d / t
v = 50 cm / 1 min
The velocity would be 50 cm/min.
To calculate the velocity, we need to divide the change in distance traveled (d) by the change in time (t). In this case, the ant traveled from the 94-cm mark to the 50-cm mark, which is a distance change of 94 cm - 50 cm = 44 cm.
The time it took for the ant to travel this distance is from 10:05 am to 10:06 am, which is 1 minute (60 seconds).
Now we can plug these values into the velocity formula: v = d / t.
v = 44 cm / 60 s = 0.73 cm/s.
Therefore, the velocity of the ant is 0.73 cm/s, not 44 cm.