Sum of two number is 16 nd product is 48. What is the difference of two numbers

12 and 4

you need to subtract the numbers

x+y=16

xy=48

4*12 = 48
...

To find the difference between two numbers, we need to first find the two numbers. Let's denote the two numbers as "x" and "y".

Given that the sum of the two numbers is 16, we can write the equation:

x + y = 16 (Equation 1)

Given that the product of the two numbers is 48, we can write another equation:

x * y = 48 (Equation 2)

To find the difference between the two numbers, we need to find the values of "x" and "y". We can solve this system of equations using algebra.

From Equation 1, we can isolate one variable. Let's solve for "x":

x = 16 - y (Equation 3)

Substituting Equation 3 into Equation 2, we get:

(16 - y) * y = 48

Expanding the equation, we have:

16y - y^2 = 48

Rearranging the equation, we get:

y^2 - 16y + 48 = 0

This is a quadratic equation. We can solve it by factoring or by using the quadratic formula. In this case, the equation can be factored as:

(y - 8)(y - 6) = 0

So, either y - 8 = 0 or y - 6 = 0.

If y - 8 = 0, then y = 8.
If y - 6 = 0, then y = 6.

Now that we've found the values of "y", we can substitute them back into Equation 3 to find the corresponding values of "x".

For y = 8, substituting into Equation 3 gives:

x = 16 - 8 = 8

For y = 6, substituting into Equation 3 gives:

x = 16 - 6 = 10

Therefore, the two numbers are 8 and 8 (or 6 and 10).

To find the difference between the two numbers, we subtract the smaller number from the larger number:

Difference = larger number - smaller number

If the two numbers are 8 and 8, then the difference is 8 - 8 = 0.
If the two numbers are 6 and 10, then the difference is 10 - 6 = 4.

So, the difference between the two numbers can be either 0 or 4, depending on the values of the numbers.