samir is twice as old as babul was two years ago.if the difference is 2 years how old is samir is?

Before 2 years ,S=2x,B=x

ATQ,
2x-x=2
x=2
so,sami's Age=2.2+2=4+2=6

s = 2(b-2)

s = b+2

b + 2 = 2 b -4
b = 6
s = 8

Let's assume the current age of Babul is x years.

According to the given information, Samir is twice as old as Babul was two years ago.
So, two years ago, Babul's age was (x - 2) years.
And the current age of Samir is twice that age, which is 2(x - 2) years.

Given that the difference in their ages is 2 years, we can set up the following equation:
2(x - 2) - x = 2

Simplifying the equation, we get:
2x - 4 - x = 2
x - 4 = 2
x = 2 + 4
x = 6

Therefore, Babul's current age is 6 years.
And Samir's age is twice that, which is:
2 * 6 = 12 years.

So, Samir is 12 years old.

To solve this problem, we can use algebraic equations. Let's denote Babul's age two years ago as B, and Samir's current age as S.

According to the problem statement, Samir is twice as old as Babul was two years ago. So, we can write the equation:

S = 2B

It is also given that the difference in their ages is 2 years. This means Samir is 2 years older than Babul. So, we can write another equation:

S - B = 2

Now, we have two equations that can be solved simultaneously to find the values of S and B.

From the first equation, we can express B in terms of S:

B = (1/2)S

Substituting this value of B into the second equation, we get:

S - (1/2)S = 2

Simplifying the equation:

(1/2)S = 2

Multiplying both sides by 2:

S = 4

So, Samir is 4 years old.