Is this the correct structure for cis-3-octene?
CH3-CH2 CH2-CH2-CH2-CH3
\ /
C=C
/ \
H H
I can't tell what you have since we can't do spacing on the computer. But I think I can draw it like this:
CH3-CH2-C=C-CH2CH2CH2CH3
Now stick a H atom to the #3 and one to the #4 C atoms, both on the same side, to make it cis.
Ok I think I have it correct but I have one more question, is there supposed to be a bond between each atom on the right side as well as the left. I see you did not put one and I did. Am I wrong? I missed this lecture in class so I am a little lost.
Thanks
No, you are not wrong. Sometimes we write it as CH3CH2CH2CH2 etc and sometimes CH3-CH2-CH2-CH2 etc.
The second way, some purists think, says that H is bonded to C without a C-C bond there but we all know what it means. If the computer would let us put in spaces, then we could write the skeleton structure as
C-C-C=C-C-C-C-C and have H atoms hanging on to the appropriate C atom but the difficulty in the spacing problem we have prevents that.
the structure of 1,2,2-trimethylcyclopentane
the structure of 1,2,2-trimethylcyclopentane
To draw the structure of 1,2,2-trimethylcyclopentane, follow these steps:
1. Start by drawing a cyclopentane ring, which consists of five carbon atoms bonded together in a ring shape.
2. Next, identify the position of the substituents (methyl groups) by using the given numbers (1, 2, 2).
3. Place three methyl groups on the cyclopentane ring:
- The first methyl group (1) should be attached to one of the carbon atoms on the ring. It doesn't matter which one you choose, as long as it is labeled as position 1.
- The second and third methyl groups (2, 2) should be attached to adjacent carbon atoms on the ring, effectively making them both positioned at the same location.
Remember to keep the geometry of the cyclopentane intact (all carbon atoms in the ring, each with one bond to the neighboring carbon atom).