10 y 11 rectangle is enlarged by 300%. How does the perimeter of an original rectangle compare to the new perimeter?
do you mean each side is enlarged by 300%?
If so, then the perimeter is also enlarged by 300%
10 x 3 = 30
So 10 height and 3 the width
To find out how the perimeter of the original 10 y 11 rectangle compares to the new perimeter after it is enlarged by 300%, we need to determine the dimensions of the enlarged rectangle.
To enlarge a rectangle by a certain percentage, we multiply each dimension of the rectangle by (1 + (percentage/100)). In this case, we need to multiply both the length and width of the original rectangle by 1 + (300/100) = 1 + 3 = 4.
So, the dimensions of the enlarged rectangle are:
Length = 10 y * 4 = 40 y
Width = 11 * 4 = 44
Now, let's calculate the perimeters of both the original and the enlarged rectangles.
Perimeter of the original rectangle:
P1 = 2 * (Length + Width)
P1 = 2 * (10 y + 11)
P1 = 2 * 21 y
P1 = 42 y
Perimeter of the enlarged rectangle:
P2 = 2 * (Enlarged Length + Enlarged Width)
P2 = 2 * (40 y + 44)
P2 = 2 * 84
P2 = 168
We can see that the new perimeter, P2, is greater than the original perimeter, P1. Therefore, the new perimeter is larger than the original perimeter after enlarging the rectangle by 300%.