A wire-wound resistor with a resistance of250ohm Will overheat if the power dissipated exceeds 10W.What is the maximum constant voltage V that can be applied across the terminals of this resistor?
power = voltage^2 / resistance
V^2/R = 10.
V^2/250 = 10.
To find the maximum constant voltage that can be applied across the terminals of the wire-wound resistor, you need to use the formula for power dissipation:
P = V^2 / R
where P is the power in watts, V is the voltage in volts, and R is the resistance in ohms.
Given that the resistance of the wire-wound resistor is 250 ohms and the maximum power dissipation is 10 W, we can rearrange the formula to solve for V:
10 = V^2 / 250
Multiply both sides of the equation by 250:
250 * 10 = V^2
2500 = V^2
Now, take the square root of both sides to find V:
V = sqrt(2500)
V ≈ 50 volts
Therefore, the maximum constant voltage that can be applied across the terminals of the resistor is approximately 50 volts.