Tonya and Lauren ate designing a soccer uniform. They want to use two colors on the shirt. Their colors are green, orange, yellow, purple, blue, and silver . How many ways can they choose two colors?

Six

Do 6×10 and your prouduct will be 60, so in my conclusions, I think my answer is 60.

To find the number of ways Tonya and Lauren can choose two colors for the soccer uniform, we can use the combination formula.

The combination formula is given by:

C(n, r) = n! / (r!(n - r)!)

Where:
- C(n, r) represents the number of combinations of n items taken r at a time.
- n! denotes the factorial of n, which is the product of all positive integers up to n.
- r! is the factorial of r.
- (n - r)! is the factorial of n minus r.

In this case, we have 6 colors to choose from (green, orange, yellow, purple, blue, and silver) and we want to choose 2 colors. Therefore, n = 6 and r = 2.

Using the combination formula, we can calculate:

C(6, 2) = 6! / (2!(6 - 2)!) = (6 * 5 * 4 * 3 * 2 * 1) / ((2 * 1) * (4 * 3 * 2 * 1)) = 15.

So, there are 15 different ways Tonya and Lauren can choose two colors for the soccer uniform.