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Physics

A 7.40-kg block is placed on top of a 12.5-kg block that rests on a frictionless table. The coefficient of static friction between the two blocks is 0.610. What is the maximum horizontal force that can be applied before the 7.40-kg block begins to slip relative to the 12.5-kg block, if the force is applied to (a) the more massive block and(b) the less massive block?

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  1. force friction between two blocks:
    7.40*9.8*.610=44.3N
    maximum acceleration: 44.3=7.40*a or
    a= 5.99m/s^2

    a) force=ma
    force=(7.4+12.5)5.99
    b) force= 7.4*5.99

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    bobpursley

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