What is the frequency in hertz of a photon of light with an energy of 3.93 x 10-21J?
What is the frequency of light in hertz with a wavelength of 4.12 x 10-7m?
energy = frequency * Planck's constant
frequency = c / wavelength
Why did the photon go to the doctor? Because it couldn't find its frequency in Hertz! Let's calculate it for you.
For the first question, we know that the energy of the photon is 3.93 x 10^-21 J. But frequency (f) and energy (E) are related by the equation E = hf, where h is Planck's constant (approximately 6.63 x 10^-34 J∙s). By rearranging the equation, we can find the frequency:
f = E / h
f = (3.93 x 10^-21 J) / (6.63 x 10^-34 J∙s)
f = (3.93 / 6.63) x 10^(-21 - (-34)) Hz
f ≈ 5.93 x 10^12 Hz
So, the frequency of the photon is approximately 5.93 x 10^12 Hz.
For the second question, we know the wavelength of the light is 4.12 x 10^-7 m. The frequency (f) and wavelength (λ) are related by the equation c = fλ, where c is the speed of light (approximately 3.00 x 10^8 m/s).
By rearranging the equation, we can find the frequency:
f = c / λ
f = (3.00 x 10^8 m/s) / (4.12 x 10^-7 m)
f ≈ 7.28 x 10^14 Hz
So, the frequency of light with a wavelength of 4.12 x 10^-7 m is approximately 7.28 x 10^14 Hz. Enjoy the light show!
To calculate the frequency of a photon of light, you can use the equation
E = hf
Where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon.
For the first question, you are given the energy of the photon as 3.93 x 10^-21 J. The value of Planck's constant is approximately 6.63 x 10^-34 J·s.
To find the frequency, rearrange the equation to solve for f:
f = E / h
Substitute the given values into the equation:
f = (3.93 x 10^-21 J) / (6.63 x 10^-34 J·s)
f ≈ 5.93 x 10^12 Hz
Therefore, the frequency of the photon of light is approximately 5.93 x 10^12 Hz.
For the second question, you are given the wavelength of the light as 4.12 x 10^-7 m. The speed of light, c, is approximately 3.00 x 10^8 m/s.
To find the frequency, you can use the equation:
c = λf
Where c is the speed of light, λ is the wavelength, and f is the frequency.
Rearrange the equation to solve for f:
f = c / λ
Substitute the given values into the equation:
f = (3.00 x 10^8 m/s) / (4.12 x 10^-7 m)
f ≈ 7.28 x 10^14 Hz
Therefore, the frequency of the light with a wavelength of 4.12 x 10^-7 m is approximately 7.28 x 10^14 Hz.
To find the frequency of a photon of light with a given energy, you can use the equation E = hf, where E is the energy of the photon, h is the Planck's constant (6.63 x 10^-34 J·s), and f is the frequency of the photon in hertz.
For the first question, the energy of the photon is given as 3.93 x 10^-21 J. To find the frequency (f), we can rearrange the equation to solve for f:
f = E / h
Plugging in the values:
f = (3.93 x 10^-21 J) / (6.63 x 10^-34 J·s)
Now, divide the numerator by the denominator:
f ≈ 5.93 x 10^12 Hz
So, the frequency of the photon of light with an energy of 3.93 x 10^-21 J is approximately 5.93 x 10^12 Hz.
Moving on to the second question, to find the frequency of light with a given wavelength, you can use the equation: c = λf, where c is the speed of light (approximately 3 x 10^8 m/s), λ is the wavelength, and f is the frequency.
In this case, we are given the wavelength as 4.12 x 10^-7 m. To find the frequency (f), rearrange the equation:
f = c / λ
Now, substitute the values:
f = (3 x 10^8 m/s) / (4.12 x 10^-7 m)
Divide the numerator by the denominator:
f ≈ 7.28 x 10^14 Hz
Therefore, the frequency of light with a wavelength of 4.12 x 10^-7 m is approximately 7.28 x 10^14 Hz.