A -A child rides a toboggan down a hill that descends at anangle of21.8◦ to thehorizontal. The hill is 42.6 m long. What is the horizontal component of the child’s displacement? Answer in units of m.

B - What is the vertical component of the child’s displacement? Answer in units of m.

For A I got 39.6 m, however how would I solve B?

To solve for the vertical component of the child's displacement, we can use trigonometry. The vertical component is equal to the length of the hill multiplied by the sine of the angle.

Given:
Angle of descent (θ) = 21.8°
Length of the hill (L) = 42.6 m

To find the vertical component (Vy):

Vy = L * sin(θ)

Vy = 42.6 m * sin(21.8°)

Using a scientific calculator, we can find:

Vy ≈ 15.35 m

Therefore, the vertical component of the child's displacement is approximately 15.35 m.

To solve for the vertical component of the child's displacement (part B), you need to use trigonometry again. Recall that the vertical component of the displacement is given by:

Vertical component = Displacement * sin(angle)

In this case, the displacement is the same as the length of the hill, which is 42.6 m. The angle is still 21.8°.

So, to find the vertical component of the displacement:

Vertical component = 42.6 m * sin(21.8°)

Using a scientific calculator or an online calculator, you can multiply 42.6 by the sine of 21.8° to get the final answer.

A. X = 42.8*Cos21.8 = 39.7 m.

B. Y = 42.8*sin21.8 = 15.9 m.