An illustrative image showing a creature running in two distinct paths. First, the creature runs 12.0 m east marked with a straight line. Then it runs 28.0 m in a direction pointing 30.0 degrees east of north, indicating a sudden change in course. The starting and ending points are clearly marked, and the overall journey visualizes a geometrical problem with the paths representing vectors. The image contains no numerical values or text.

Kalibasib runs 12.0 m east and then 28.0 m in a direction 30.0 degrees east of north. How

far is Kalibasib from the starting point?

make a sketch, then use the cosine law:

x^2 = 12^2 + 26^2 - 2(12)(28)cos120°
= 144 + 676 - (-336)
= 1156
x = √1156 = 34

Well, if Kalibasib ran east and then east of north, it seems like they're running in circles trying to find their way. Maybe they should consider investing in a GPS instead of relying on their sense of direction!

But to answer your question, we can use some good old trigonometry to calculate the distance. The horizontal component of the second leg (28.0 m) would be 28.0 m * cos(30°), which is approximately 24.2 m.

Now, if we combine the horizontal displacement of the first leg (12.0 m east) and the second leg (24.2 m east), we get a total horizontal displacement of 36.2 m east.

To find the distance from the starting point, we can use the Pythagorean theorem. The distance would be the square root of (36.2 m)^2 + (28.0 m)^2, which is approximately 46.6 m. So, Kalibasib is approximately 46.6 meters away from the starting point. But hey, at least they got some exercise in the process, right?

To find the distance from the starting point, we can use the Pythagorean theorem.

Step 1: Calculate the eastward component of the displacement.
Given: Kalibasib runs 12.0 m east.
The eastward component is the distance in the eastward direction, which is 12.0 m.

Step 2: Calculate the northward component of the displacement.
Given: Kalibasib runs 28.0 m in a direction 30.0 degrees east of north.
To find the northward component, we can use trigonometry.
The northward component is given by the formula: distance * sin(angle).
distance = 28.0 m
angle = 30.0 degrees
northward component = 28.0 m * sin(30.0 degrees) = 14.0 m

Step 3: Use the Pythagorean theorem to find the distance from the starting point.
The Pythagorean theorem states that the square of the hypotenuse (distance from the starting point) is equal to the sum of the squares of the other two sides.
distance^2 = (eastward component)^2 + (northward component)^2
distance^2 = 12.0 m^2 + 14.0 m^2
distance^2 = 144.0 m^2 + 196.0 m^2
distance^2 = 340.0 m^2
distance = sqrt(340.0 m^2)
distance ≈ 18.4 m

So, Kalibasib is approximately 18.4 m from the starting point.

To find the distance Kalibasib is from the starting point, we can use the concept of vector addition. We need to break down the given displacement vectors into their horizontal (east) and vertical (north) components.

First, let's calculate the horizontal displacement:
Kalibasib runs 12.0 m east. Since this is already in the east direction, the horizontal (east) component remains 12.0 m.

Next, let's calculate the vertical displacement:
Kalibasib runs 28.0 m in a direction 30.0 degrees east of north. To find the north component, we need to use trigonometry. The north component can be calculated as follows:
North component = 28.0 m * cos(30 degrees)

Using the trigonometric identity cos(30 degrees) = √3/2, we can calculate the north component:
North component = 28.0 m * (√3/2) ≈ 48.49 m

Now that we have the horizontal and vertical components, we can use the Pythagorean theorem to find the distance:
Distance = √[(horizontal displacement)^2 + (vertical displacement)^2]
Distance = √[(12.0 m)^2 + (48.49 m)^2]
Distance ≈ √[144 + 2350.0801]
Distance ≈ √2494.0801
Distance ≈ 49.94 m

Therefore, Kalibasib is approximately 49.94 m away from the starting point.