of all the houses in a certain neighborhood,80 % have garages.Of those houses with garages 60% have two car garages.If there are 56 houses with garages that are not two car garages,how many houses are there in the neighborhood.

How do I do this using percent change ?

there is no change involved. If there are x houses in total, then

.80x have garages
60% of those have two-car garages, so 40% have garages that are not two-car.

.80x * .40 = 56
x = 175

To solve this problem using percent change, we need to understand the given information and apply simple math calculations. Let's break it down step by step:

1. Given information:
- 80% of all houses in the neighborhood have garages.
- Out of the houses with garages, 60% have two-car garages.
- 56 houses with garages are not two-car garages.

2. Calculating the total number of houses with garages:
- Since 80% of houses have garages, we can assume that 80 out of every 100 houses have garages.
- Let's represent the total number of houses with garages as x.
- So, we can calculate that 80/100 * x = x * 0.8 = 0.8x.

3. Calculating the number of houses with two-car garages:
- Since 60% of the houses with garages have two-car garages, we can calculate that 0.6 * 0.8x = 0.48x.

4. Calculating the number of houses that are not two-car garages:
- We are given that there are 56 houses with garages that are not two-car garages.
- So, we can set up the equation 0.8x - 0.48x = 56 to find the value of x.

5. Solving for x:
- Simplifying the equation, we get 0.32x = 56.
- Dividing both sides by 0.32, we find x = 56 / 0.32 = 175.

Therefore, there are a total of 175 houses in the neighborhood.