IT TAKES 5 MEN 7 HOURS TO DIG 9 HOLES, HOW MANY HOURS/MINUTES DOES IT TAKE 1 MAN TO DIG A HALF A HOLE?
5 men for 7 hours to dig 9 holes
1 man for 7 hours to dig 9/5 holes
1 man for 7 ÷(9/5) hours to dig 1 hole
1 man for 35/9 hours to dig 1 hole
1 man for 35/18 hours to dig 1/2 hole
35/18 hours = 35/18 * 60 minutes
= 116 2/3 minutes
or
it took 35 man hours to dig 9 holes
it will take 35/9 man hours to dig 1 hole
it will take 35/18 man hours to dig 1/2 hole
but since we only have 1 man working it will take
35/18 hours , same as above
What is a half a hole?
To solve this problem, we can use the concept of man-hours, which is a measure of the total workforce required to complete a task in a certain amount of time.
We know that 5 men can dig 9 holes in 7 hours. Let's calculate the total man-hours required to dig these 9 holes:
Total man-hours = number of men × number of hours = 5 × 7 = 35 man-hours.
Now, we want to find out how many hours or minutes it takes for one man to dig half a hole.
First, let's calculate the total man-hours required to dig half a hole:
Total man-hours = number of men × number of hours = 1 × x, where x is the unknown number of hours.
Now we can set up a proportion to solve for x:
5 men / 35 hours = 1 man / x hours
Cross-multiplying, we get:
5x = 35
Dividing both sides by 5, we find:
x = 7
Therefore, it would take one man 7 hours to dig half a hole.