Do you factor 9x^2 +7x-56
no.
at least, not with rational coefficients.
My feet hurt.
Yes, I can help you factor the quadratic expression 9x^2 + 7x - 56.
To factor this expression, we need to find two binomial factors that multiply together to give us the original expression. Here's how we can do it:
Step 1: Multiply the coefficient of the x^2 term (9) by the constant term (-56). The result is -504.
Step 2: Now we need to find two numbers whose product is -504 and whose sum is equal to the coefficient of the x term (7). In this case, the numbers are 28 and -18.
Step 3: Rewrite the middle term of the quadratic expression (7x) using these two numbers. This means we replace the 7x term with 28x and -18x.
So, now we have 9x^2 + 28x - 18x - 56.
Step 4: Factor by grouping. Group the terms together:
(9x^2 + 28x) + (-18x - 56).
Step 5: Now, factor out the greatest common factor from each group:
x(9x + 28) - 7(9x + 28).
Step 6: Notice that the terms in parentheses are the same, so we can factor out the common binomial factor:
(9x + 28)(x - 7).
Therefore, the factored form of the quadratic expression 9x^2 + 7x - 56 is (9x + 28)(x - 7).