Chemistry
How much energy (in Joules) is required to heat 10.48 g of water from 12.7 oC to 46.3 oC ? Use 4.184 J/goC as the specific heat capacity of water.
53 g of water at 81.5 oC is added to a calorimeter that contains 50.52 g of water at 40.6 oC. If the final temperature of the system is 59.4 oC, what is the calorimeter constant (Ccalorimeter) ? Use 4.184 J/goC for the heat capacity of water.
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Lee

q = mass H2O x specific heat water x (TfinalTintial)
sp.h. stands for specific heat and qcal is calorimeter constant.
mass warm H2O x sp.h.H2O x (TfinalTinitial) + mass cool H2O x (TfinalTinitial) + qcal(TfinalTinitial) and solve for qcal.
Post your work if you get stuck. _posted by DrBob222
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