3. 0.1825 g of Fe(NH4)2(SO4)2•6H2O is dissolved in 250.00 mL of solution; this is Solution A. 5.00 mL of Solution A is transferred to another flask, and it is diluted to a total of 100.0 mL to make another solution, which is Solution B. Next, 3.00 mL of Solution B is diluted to a total of 10.0 mL to make Solution C.

a) what is the molar concentration of Solution A?

b) what is the molar concentration of Solution B?

c) what is the molar concentration of Solution C?

To find the molar concentration of each solution, we need to first calculate the number of moles of solute and then divide it by the volume of the solution in liters.

a) Molar concentration of Solution A:
1. Calculate the number of moles of Fe(NH4)2(SO4)2•6H2O in Solution A:
Given mass of Fe(NH4)2(SO4)2•6H2O = 0.1825 g
Molar mass of Fe(NH4)2(SO4)2•6H2O = (2 * atomic mass of Fe) + (2 * atomic mass of N) + (8 * atomic mass of H) + (4 * atomic mass of S) + (24 * atomic mass of O)
= (2 * 55.85) + (2 * 14.01) + (8 * 1.01) + (4 * 32.07) + (24 * 16.00)
= 392.14 g/mol

Number of moles of Fe(NH4)2(SO4)2•6H2O in Solution A = (Given mass of Fe(NH4)2(SO4)2•6H2O) / (Molar mass of Fe(NH4)2(SO4)2•6H2O)
= 0.1825 g / 392.14 g/mol

2. Convert the volume of Solution A to liters:
Given volume of Solution A = 250.00 mL
= 250.00 mL * (1 L / 1000 mL)

3. Calculate the molar concentration of Solution A:
Molar concentration of Solution A = (Number of moles of solute) / (Volume of Solution A in liters)

b) Molar concentration of Solution B:
Since 5.00 mL of Solution A is transferred to a 100.0 mL flask and diluted to a total volume, we assume that the number of moles of solute remains the same.

1. Convert the volumes of Solution A and Solution B to liters:
Volume of Solution A = 5.00 mL * (1 L / 1000 mL)
Volume of Solution B = 100.0 mL * (1 L / 1000 mL)

2. Calculate the molar concentration of Solution B:
Molar concentration of Solution B = (Number of moles of solute) / (Volume of Solution B in liters)

c) Molar concentration of Solution C:
Since 3.00 mL of Solution B is transferred to a 10.0 mL flask and diluted to a total volume, we assume that the number of moles of solute remains the same.

1. Convert the volumes of Solution B and Solution C to liters:
Volume of Solution B = 3.00 mL * (1 L / 1000 mL)
Volume of Solution C = 10.0 mL * (1 L / 1000 mL)

2. Calculate the molar concentration of Solution C:
Molar concentration of Solution C = (Number of moles of solute) / (Volume of Solution C in liters)