a base ball diamond is a square. the distance from the home plate to first base is 90 feet. in feet, what is distance from home plate to second base?

A.127
B.81
C.19
D.13
I think it is A?

90 √2

What does thst even mean?

81 To find the distance from home plate to second base on a baseball diamond, you need to use the Pythagorean theorem. The distance between two bases on a square diamond is the hypotenuse of a right-angled triangle, with the two sides representing the distances from home plate to first base and first base to second base.

Given that the distance from home plate to first base is 90 feet, and assuming the bases are all equidistant, we can consider the triangle formed by the home plate, first base, and the desired distance to second base.

Using the Pythagorean theorem, we have:

a^2 + b^2 = c^2,

where a represents the distance from home plate to first base (90 feet), b represents the distance from first base to second base, and c represents the desired distance from home plate to second base.

Rearranging the equation for b, we have:

b = √(c^2 - a^2).

Substituting the given values, we get:

b = √(c^2 - 90^2).

Now, we can check the answer choices using these calculations:

A. √(127^2 - 90^2) = √(16129 - 8100) = √8030 ≈ 89.6 (approximately)

B. √(81^2 - 90^2) = √(6561 - 8100) = √( -1539) (not possible, as we cannot have a negative distance)

C. √(19^2 - 90^2) = √(361 - 8100) = √( -7739) (not possible, as we cannot have a negative distance)

D. √(13^2 - 90^2) = √(169 - 8100) = √( -7931) (not possible, as we cannot have a negative distance)

Therefore, the correct answer is A. The distance from home plate to second base is approximately 89.6 feet.