a boy travel 5km east and then12
km south.calculate his displacement from starting point.
Draw a line to the left and then down. You have just drawn a triangle! Then use Pythagorean rule of A^2 + B^2 = C^2 (A squared plus B squared equals C squared.) The displacement will be the value of C.
5
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You have been given the legs A=5 and B=12. Solve by placing into A^2 + B^2 = C^2
Well my triangle didn't draw so I'll try again.
5
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[][][][][][]▼ 12
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If you need more help. Solve the rest of this.
5^2 + 12^2 = C^2
25 + 144 = C^2
169 = C^2
13 is the distance, however displacement is a vector.
x = 5 (east is right)
y = -13 (south is down
A = angle south of east
tan A = 13/5
A = 69 degrees
angle counterclockwise from x (east)
= 360 - 69 = 291
magnitude = 13
To calculate the displacement of the boy from his starting point, we need to find the straight-line distance between the starting point and the final position.
Here's how to solve it step by step:
1. Create a coordinate system: Assume the starting point is the origin (0,0) on a graph, where east is the positive x-axis, and north is the positive y-axis.
2. Plot the movement: The boy travels 5 km east, which means he moves 5 units along the x-axis to the point (5, 0). Then, he travels 12 km south, which means he moves 12 units along the negative y-axis to the point (5, -12).
3. Find the displacement: To calculate the displacement, we need to find the straight-line distance between the starting point (0,0) and the final position (5, -12). We can use the distance formula, which is the square root of the sum of the squares of the differences between the coordinates:
Displacement = √((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates, we get:
Displacement = √((5 - 0)^2 + (-12 - 0)^2)
= √(5^2 + (-12)^2)
= √(25 + 144)
= √169
= 13 km
Therefore, the boy's displacement from the starting point is 13 km.