physics

a boy travel 5km east and then12
km south.calculate his displacement from starting point.

asked by kelly
  1. Draw a line to the left and then down. You have just drawn a triangle! Then use Pythagorean rule of A^2 + B^2 = C^2 (A squared plus B squared equals C squared.) The displacement will be the value of C.

    5
    ▶▶▶▶▶
    [][][]▼
    [][][]▼ 12
    [][][]▼
    [][][]▼
    [][][]▼

    You have been given the legs A=5 and B=12. Solve by placing into A^2 + B^2 = C^2

    posted by Anonymous
  2. Well my triangle didn't draw so I'll try again.

    5
    ▶▶▶▶▶
    [][][][][][]▼
    [][][][][][]▼ 12
    [][][][][][]▼
    [][][][][][]▼
    [][][][][][]▼

    If you need more help. Solve the rest of this.
    5^2 + 12^2 = C^2
    25 + 144 = C^2
    169 = C^2

    posted by Anonymous
  3. 13 is the distance, however displacement is a vector.
    x = 5 (east is right)
    y = -13 (south is down

    A = angle south of east
    tan A = 13/5
    A = 69 degrees

    angle counterclockwise from x (east)
    = 360 - 69 = 291
    magnitude = 13

    posted by Damon

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