The United States and South Korean soccer teams are playing in the first round of the World Cup. An American kicks the ball, giving it an initial velocity of 3.6 m/s. The ball rolls a distance of 5.0 m and is then intercepted by a South Korean player. If the ball accelerates at -0.50 m/s2 while rolling along the grass, find its velocity at the time of interception. (2sigfigs)

V^2 = Vo^2 + 2a^d.

V^2 = (3.6)^2 - 2*0.5*5.
V = ?.

To find the velocity of the ball at the time of interception, we can use the kinematic equation:

v^2 = u^2 + 2as

Where:
v = final velocity
u = initial velocity
a = acceleration
s = distance

Given:
u = 3.6 m/s (initial velocity)
a = -0.50 m/s^2 (acceleration)
s = 5.0 m (distance)

First, let's find the final velocity squared. Rearranging the equation, we have:

v^2 = u^2 + 2as

v^2 = (3.6 m/s)^2 + 2(-0.50 m/s^2)(5.0 m)

v^2 = 12.96 m^2/s^2 + (-5.00 m^2/s^2)

v^2 = 7.96 m^2/s^2

Now, take the square root of both sides to find the velocity:

v = √7.96 m^2/s^2

v ≈ 2.82 m/s (rounded to 2 significant figures)

Therefore, the velocity of the ball at the time of interception is approximately 2.82 m/s.